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0=12x^2-8x-60
We move all terms to the left:
0-(12x^2-8x-60)=0
We add all the numbers together, and all the variables
-(12x^2-8x-60)=0
We get rid of parentheses
-12x^2+8x+60=0
a = -12; b = 8; c = +60;
Δ = b2-4ac
Δ = 82-4·(-12)·60
Δ = 2944
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2944}=\sqrt{64*46}=\sqrt{64}*\sqrt{46}=8\sqrt{46}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-8\sqrt{46}}{2*-12}=\frac{-8-8\sqrt{46}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+8\sqrt{46}}{2*-12}=\frac{-8+8\sqrt{46}}{-24} $
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